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# 实验4

2周前 (04-29) 7次浏览
```#include <stdio.h>
long long fun(int n);

int main() {
int n;
long long f;

while(scanf("%d", &n) != EOF) {
f = fun(n);
printf("n = %d, f = %lldn", n, f);
}

return 0;
}

long long fun(int n){
if(n==1)
{return 1;
}
else
{return 2*fun(n-1)+1;
}

}```

```#include <stdio.h>
long long fac(int n); // 函数声明

int main() {
int i,n;

printf("Enter n: ");
scanf("%d", &n);

for(i=1; i<=n; ++i)
printf("%d! = %lldn", i, fac(i));

return 0;
}

// 函数定义
long long fac(int n) {
static long long p = 1;
p = p*n;

return p;
}```

2.

```// 利用局部static变量计算阶乘

#include <stdio.h>
long long fac(int n); // 函数声明

int main() {
int i,n;

printf("Enter n: ");
scanf("%d", &n);

for(i=1; i<=n; ++i)
printf("%d! = %lldn", i, fac(i));

return 0;
}

// 函数定义
long long fac(int n) {
static long long p = 1;
printf("p=%lldn",p);
p = p*n;

return p;
}```

```#include<stdio.h>
int func(int, int);

int main() {
int k=4,m=1,p1,p2;

p1 = func(k,m) ;
p2 = func(k,m) ;
printf("%d,%dn",p1,p2) ;

return 0;
}

int func(int a,int b) {
static int m=0,i=2;

i += m+1;
m = i+a+b;

return (m);
}```

3.

```#include <stdio.h>
#define N 1000
int fun(int n,int m,int bb[N]) {
int i,j,k=0,flag;

for(j=n;j<=m;j++) {
flag=1;
for(i=2;i<j;i++)
if(j%i==0) {
flag=0;
break;
}
if(flag!=0)
bb[k++]=j;
}
return k;
}

int main(){
int n=0,m=0,i,k,bb[N];

scanf("%d",&n);
scanf("%d",&m);

for(i=0;i<m-n;i++)
bb[i]=0;

k=fun(n,m,bb);

for(i=0;i<k;i++)
printf("%4d",bb[i]);

return 0;
}```

4.

```#include <stdio.h>
void dec2n(int x, int n);

int main() {
int x;

printf("输入一个十进制整数: ");
scanf("%d", &x);

dec2n(x, 2);
dec2n(x, 8);
dec2n(x, 16);

return 0;
}
void dec2n(int x, int n)
{
int i;
char m;
int change[1000];

for(i=0;x!=0;i++)
{
change[i]=x%n;
x=x/n;
}

for(i=i-1;i>=0;i--)
{
if(change[i]>=10)
{
m=55+change[i];
printf("%c",m);
}
else
printf("%d",change[i]);
}

printf("n");
}```