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# leetcode刷题2

1周前 (04-07) 3次浏览
`class ListNode(object):    def __init__(self, val=0, next=None):        self.val = val        self.next = nextclass Linklist(object):    def __init__(self):        self._head = Nonelist1 = [2, 4, 5, 9]list2 = [5, 6, 4]n1 = ListNode()n2 = ListNode()temp1 = n1temp2 = n2for i in range(len(list1)): #建立了以n1为起始节点的链表n1    if i == 0:        n1.val = list1[0]    else:        temp1.next = ListNode(list1[i])        temp1 = temp1.nextfor j in range(len(list2)):  #以n2为起始点的链表n2    if j == 0:        n2.val = list2[0]    else:        temp2.next = ListNode(list2[j])        temp2 = temp2.nextclass Solution(object):    def addTwoNumbers(self, l1:ListNode, l2:ListNode) -> ListNode:        flag = 0        next_sum = 0        res = ListNode()        temp = res        size3 = 0        while l1 != None and l2 != None:            if flag == 0:                p = l1.val + l2.val                res.val = p % 10                next_sum = int(p/10)                flag += 1            else:                p = l1.val + l2.val + next_sum                next_sum = int(p/10)                temp.next = ListNode(p%10)                temp = temp.next            l1 = l1.next            l2 = l2.next            size3 += 1        while l1:            p = l1.val + next_sum            next_sum = int(p/10)            temp.next = ListNode(p%10)            temp = temp.next            l1 = l1.next            size3 += 1        while l2:            p = l2.val + next_sum            next_sum = int(p/10)            temp.next = ListNode(p%10)            temp = temp.next            l2 = l2.next            size3 += 1        if next_sum != 0:            temp.next = ListNode(next_sum)            size3 += 1        return res, size3s = Solution()n3, size3 = s.addTwoNumbers(n1, n2)for i in range(size3):    print(n3.val)    n3 = n3.next`